The reaction of 1-chlorobutane with alcoholic | vedclass

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Question

(A) The reaction of $1-$chlorobutane $(CH_3CH_2CH_2CH_2Cl)$ with alcoholic $KOH$ is a dehydrohalogenation reaction (an elimination reaction). In this

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$1-$butene

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(A) The reaction of $1-$chlorobutane $(CH_3CH_2CH_2CH_2Cl)$ with alcoholic $KOH$ is a dehydrohalogenation reaction (an elimination reaction). In this reaction,the base $(OH^-)$ abstracts a proton from the $\beta$-carbon,leading to the formation of an alkene. $CH_3CH_2CH_2CH_2Cl + KOH (	ext{alc.}) ightarrow CH_3CH_2CH=CH_2 + KCl + H_2O$. The product formed is $1-$butene.

The reaction of $1-$chlorobutane with alcoholic potassium hydroxide $(KOH)$ yields .....................

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