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(B) The reactivity of alkyl halides towards $S_{N^1}$ reaction depends on the stability of the carbocation intermediate formed after the loss of the l

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$II > III > I$

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(B) The reactivity of alkyl halides towards $S_{N^1}$ reaction depends on the stability of the carbocation intermediate formed after the loss of the leaving group $(Cl^-)$.$1$. For $(I)$,$CH_3CH_2CH_2Cl$ forms a $1^{\circ}$ carbocation $(CH_3CH_2CH_2^+)$,which is the least stable.$2$. For $(III)$,$CH_3CH_2CH(Cl)CH_3$ forms a $2^{\circ}$ carbocation $(CH_3CH_2CH^+CH_3)$,which is more stable than a $1^{\circ}$ carbocation.$3$. For $(II)$,$CH_2 = CH - CH(Cl)CH_3$ forms an allylic carbocation $(CH_2 = CH - CH^+CH_3)$. This carbocation is resonance-stabilized,making it the most stable among the three.Therefore,the order of stability of carbocations is $(II) > (III) > (I)$.Thus,the decreasing order of reactivity towards $S_{N^1}$ is $II > III > I$.

Arrange the following halides in the decreasing order of their reactivity towards $S_{N^1}$ reaction.
$(I) \ CH_3CH_2CH_2Cl$ $(II) \ CH_2 = CH - CH(Cl)CH_3$
$(III) \ CH_3CH_2CH(Cl)CH_3$

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Arrange the following halides in the decreasing order of their reactivity towards $S_{N^1}$ reaction.$(I) \ CH_3CH_2CH_2Cl$ $(II) \ CH_2 = CH - CH(Cl)CH_3$$(III) \ CH_3CH_2CH(Cl)CH_3$