The order of reactivity of the following hali | vedclass

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(A) The reactivity of halides towards $S_{N}1$ reaction depends on the stability of the carbocation intermediate formed.More stable the carbocation,fa

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$(3) > (2) > (1) > (4) > (5)$

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(A) The reactivity of halides towards $S_{N}1$ reaction depends on the stability of the carbocation intermediate formed.More stable the carbocation,faster is the $S_{N}1$ reaction.Stability order of carbocations:$(3) \ (C_6H_5)_2C^+(CH_3)$ is a tertiary carbocation stabilized by two phenyl rings and one methyl group.$(2) \ (C_6H_5)_2CH^+$ is a secondary carbocation stabilized by two phenyl rings.$(1) \ (CH_3)_3C^+$ is a tertiary carbocation stabilized by three methyl groups (inductive effect).$(4) \ (CH_3)_2CH^+$ is a secondary carbocation stabilized by two methyl groups.$(5) \ C_2H_5^+$ is a primary carbocation.Comparing the stability: $(3) > (2) > (1) > (4) > (5)$.Therefore,the order of reactivity is $(3) > (2) > (1) > (4) > (5)$.

The order of reactivity of the following halides towards $S_{N}1$ reaction is:
$(1) \ (CH_3)_3CBr$
$(2) \ (C_6H_5)_2CHBr$
$(3) \ (C_6H_5)_2C(CH_3)Br$
$(4) \ (CH_3)_2CHBr$
$(5) \ C_2H_5Br$

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The order of reactivity of the following halides towards $S_{N}1$ reaction is:$(1) \ (CH_3)_3CBr$ $(2) \ (C_6H_5)_2CHBr$ $(3) \ (C_6H_5)_2C(CH_3)Br$ $(4) \ (CH_3)_2CHBr$ $(5) \ C_2H_5Br$