The product of the reaction is .....

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(C) The reaction involves the nucleophilic substitution of a chiral haloalkane with aqueous $NaOH$. Since the substrate is a secondary alkyl halide,th

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(C) The reaction involves the nucleophilic substitution of a chiral haloalkane with aqueous $NaOH$. Since the substrate is a secondary alkyl halide,the reaction proceeds via an $S_N2$ mechanism. In an $S_N2$ reaction,the nucleophile $(OH^-)$ attacks from the side opposite to the leaving group $(Cl^-)$,resulting in the inversion of configuration (Walden inversion). Starting with the given Fischer projection,the $Cl$ atom is on the right. After the $S_N2$ inversion,the $OH$ group will be on the left side,while the other groups ($H$ and $CH_3$) remain in their positions. Therefore,the correct product is the structure with $HO$ on the left,$H$ on top,$I$ on the right,and $CH_3$ on the bottom.

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