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(D) The reaction involves the dehydrohalogenation of a vicinal dibromide $(Ph-CH(Br)-CH(Br)-CHO)$ in the presence of a base $(K_2CO_3)$ and heat $(\De

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$Ph-CH=C(Br)-CHO$

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(D) The reaction involves the dehydrohalogenation of a vicinal dibromide $(Ph-CH(Br)-CH(Br)-CHO)$ in the presence of a base $(K_2CO_3)$ and heat $(\Delta)$.This is an elimination reaction (specifically $E2$ mechanism).The base abstracts a proton from the carbon adjacent to the bromine, leading to the formation of a double bond and the elimination of $HBr$.In the given molecule, the proton on the carbon attached to the aldehyde group ($\alpha$-carbon) is more acidic due to the electron-withdrawing effect of the $-CHO$ group.Therefore, the elimination occurs to form the conjugated product: $Ph-CH=C(Br)-CHO$.

Identify the structure of the major product in the following reaction:
$Ph-CH(Br)-CH(Br)-CHO \xrightarrow[\Delta]{K_2CO_3} ?$

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Identify the structure of the major product in the following reaction:$Ph-CH(Br)-CH(Br)-CHO \xrightarrow[\Delta]{K_2CO_3} ?$