The possible products formed in the following | vedclass

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(B) The reactant is a secondary alkyl halide ($2^\circ$ halide) attached to a tetralin ring system. $NaC \equiv CH$ is a strong base and a nucleophile

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$II, III, IV$

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(B) The reactant is a secondary alkyl halide ($2^\circ$ halide) attached to a tetralin ring system. $NaC \equiv CH$ is a strong base and a nucleophile. Since the substrate is a secondary halide,both $S_N2$ (substitution) and $E2$ (elimination) reactions can occur. $1$. $S_N2$ reaction: The acetylide ion acts as a nucleophile and attacks the carbon atom,resulting in the substitution of $X$ with the $-C \equiv CH$ group. This gives product $(IV)$. $2$. $E2$ reaction: The acetylide ion acts as a base and abstracts a proton from the adjacent carbon atoms. - Abstraction of a proton from the $C_1$ position leads to the formation of a double bond between $C_1$ and $C_2$,resulting in product $(III)$. - Abstraction of a proton from the $C_3$ position leads to the formation of a double bond between $C_2$ and $C_3$,resulting in product $(II)$. Product $(I)$ is not possible as it involves a rearrangement of the aromatic ring. Therefore,the possible products are $(II)$,$(III)$,and $(IV)$.

The possible products formed in the following reaction are:

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