20 mL of 0.5 N HCl and 35 mL of 0.1 N N | vedclass

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(D) Step $1$: Calculate the milliequivalents of $HCl$ and $NaOH$.$mEq 	ext{ of } HCl = 20 \ mL 	imes 0.5 \ N = 10 \ mEq$.$mEq 	ext{ of } NaOH = 35

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Turn methyl orange red

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(D) Step $1$: Calculate the milliequivalents of $HCl$ and $NaOH$.$mEq 	ext{ of } HCl = 20 \ mL 	imes 0.5 \ N = 10 \ mEq$.$mEq 	ext{ of } NaOH = 35 \ mL 	imes 0.1 \ N = 3.5 \ mEq$.Step $2$: Determine the nature of the resulting solution.Since $mEq 	ext{ of } HCl > mEq 	ext{ of } NaOH$,the solution is acidic.$mEq 	ext{ of } H^+ 	ext{ remaining} = 10 - 3.5 = 6.5 \ mEq$.Step $3$: Analyze the indicators.Phenolphthalein is colorless in acidic medium and pink in basic medium. Methyl orange is red in acidic medium $(pH  4.4)$.Calculating the final concentration of $H^+$:$[H^+] = \frac{6.5 \ mEq}{55 \ mL} \approx 0.118 \ N$.$pH = -\log(0.118) \approx 0.93$.At $pH \approx 0.93$,methyl orange turns red. Therefore,the correct option is $D$.

$20 \ mL$ of $0.5 \ N \ HCl$ and $35 \ mL$ of $0.1 \ N \ NaOH$ are mixed. The resulting solution will

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