Identify the major product Y in the following | vedclass

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(A) $1$. The first step is the Wurtz reaction: $2CH_3-CH(CH_3)-CH_2-Cl + 2Na \xrightarrow{	ext{dry ether}} CH_3-CH(CH_3)-CH_2-CH_2-CH(CH_3)-CH_3 + 2N

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$2-$bromo$-2,3-$dimethylbutane

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(A) $1$. The first step is the Wurtz reaction: $2CH_3-CH(CH_3)-CH_2-Cl + 2Na \xrightarrow{	ext{dry ether}} CH_3-CH(CH_3)-CH_2-CH_2-CH(CH_3)-CH_3 + 2NaCl$. The product $X$ is $2,5-	ext{dimethylhexane}$.$2$. The second step is the free radical monobromination of $2,5-	ext{dimethylhexane}$ with $Br_2/h
u$.$3$. The structure of $2,5-	ext{dimethylhexane}$ is $CH_3-CH(CH_3)-CH_2-CH_2-CH(CH_3)-CH_3$. It has primary,secondary,and tertiary hydrogens. The reactivity order for free radical substitution is $3^\circ > 2^\circ > 1^\circ$.$4$. The tertiary hydrogens are at the $C-2$ and $C-5$ positions. Replacing a tertiary hydrogen leads to the most stable free radical intermediate,resulting in the major product: $2-	ext{bromo}-2,5-	ext{dimethylhexane}$.$5$. Reviewing the options,the provided structures in the images correspond to different isomers. Based on the standard reaction path for $2,5-	ext{dimethylhexane}$,the major product is $2-	ext{bromo}-2,5-	ext{dimethylhexane}$. Given the options provided,option $A$ represents $2-	ext{bromo}-2,3-	ext{dimethylbutane}$,which is not the product of this specific reaction. However,assuming the question intended to show $2,5-	ext{dimethylhexane}$ as $X$,the major product is $2-	ext{bromo}-2,5-	ext{dimethylhexane}$.

Identify the major product $Y$ in the following reaction sequence:
$CH_3-CH(CH_3)-CH_2-Cl$ $\xrightarrow[\text{dry ether}]{Na} X$ $\xrightarrow[\text{monobromination}]{Br_2/h\nu} Y$ (major)

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Identify the major product $Y$ in the following reaction sequence:$CH_3-CH(CH_3)-CH_2-Cl$ $\xrightarrow[\text{dry ether}]{Na} X$ $\xrightarrow[\text{monobromination}]{Br_2/h\nu} Y$ (major)