(B) Number of $Ca^{2+}$ ions at corners $= 8 \times \frac{1}{8} = 1$. Number of $Ti$ ions at body center $= 1$. Number of $O^{2-}$ ions at face center

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(B) Number of $Ca^{2+}$ ions at corners $= 8 \times \frac{1}{8} = 1$. Number of $Ti$ ions at body center $= 1$. Number of $O^{2-}$ ions at face centers $= 6 \times \frac{1}{2} = 3$. Thus,the formula is $CaTiO_3$. Let the oxidation state of $Ti$ be $x$. $(+2) + x + 3(-2) = 0 2 + x - 6 = 0 x = +4$. Therefore,the formula is $CaTiO_3$ and the oxidation state of $Ti$ is $+4$.

Class 12 Chemistry Solid State Crystal structure and Coordination number

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$A$ compound contains $Ca, Ti$ and $O$ elements. If $Ca^{2+}$ ions are at the corners of the cube,$Ti$ ions are at the body center,and $O^{2-}$ ions are at the face centers,then the molecular formula of the compound and the oxidation state of $Ti$ are respectively ........

A
$CaTi_2O_3, +2$
B
$CaTiO_3, +4$
C
$CaTi_3O_4, +2$
D
$CaTiO_2, +2$

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Solid State

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Crystal structure and Coordination number

In sodium chloride,$Cl^-$ ions form a $ccp$ arrangement. In this structure,where are the $Na^+$ ions located?

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In $NaCl$ type structure, the shortest distance between two nearest neighbours is $100 \ pm$. Then, the distance between two next nearest neighbours in the same unit cell will be:

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In the face-centred cubic $(FCC)$ lattice structure of gold, the closest distance between gold atoms is ('a' being the edge length of the cubic unit cell).

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The arrangement of $X^{-}$ ions around $A^{+}$ ion in solid $AX$ is given in the figure. If the radius of $X^{-}$ is $250 \ pm$, the radius of $A^{+}$ is: (in $pm$)

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In a face-centered cubic arrangement of atoms $A$ and $B$,atoms $A$ are at the corners of the unit cell and atoms $B$ are at the face centers. If one atom $A$ is missing from one corner of the unit cell,what is the simplest formula of the compound?

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$A$ compound contains $Ca, Ti$ and $O$ elements. If $Ca^{2+}$ ions are at the corners of the cube,$Ti$ ions are at the body center,and $O^{2-}$ ions are at the face centers,then the molecular formula of the compound and the oxidation state of $Ti$ are respectively ........

Similar Questions

In sodium chloride,$Cl^-$ ions form a $ccp$ arrangement. In this structure,where are the $Na^+$ ions located?

In $NaCl$ type structure, the shortest distance between two nearest neighbours is $100 \ pm$. Then, the distance between two next nearest neighbours in the same unit cell will be:

In the face-centred cubic $(FCC)$ lattice structure of gold, the closest distance between gold atoms is ('a' being the edge length of the cubic unit cell).

The arrangement of $X^{-}$ ions around $A^{+}$ ion in solid $AX$ is given in the figure. If the radius of $X^{-}$ is $250 \ pm$, the radius of $A^{+}$ is: (in $pm$)

In a face-centered cubic arrangement of atoms $A$ and $B$,atoms $A$ are at the corners of the unit cell and atoms $B$ are at the face centers. If one atom $A$ is missing from one corner of the unit cell,what is the simplest formula of the compound?

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