In a ccp structure of X atoms,Y atoms occupy | vedclass

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(A) In a $ccp$ unit cell,the total number of $X$ atoms at corners and face centers is $4$. The number of octahedral voids is equal to the number of at

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$X_{15}Y_{16}Z$

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(A) In a $ccp$ unit cell,the total number of $X$ atoms at corners and face centers is $4$. The number of octahedral voids is equal to the number of atoms,which is $4$.Number of $X$ atoms remaining after replacing $2$ corner atoms: $X = 4 - (2 	imes \frac{1}{8}) = 4 - \frac{1}{4} = \frac{15}{4}$.Number of $Y$ atoms in octahedral voids: $Y = 4$.Number of $Z$ atoms replacing corner atoms: $Z = 2 	imes \frac{1}{8} = \frac{1}{4}$.The ratio is $X : Y : Z = \frac{15}{4} : 4 : \frac{1}{4}$.Multiplying by $4$,we get $X_{15}Y_{16}Z$.

In a $ccp$ structure of $X$ atoms,$Y$ atoms occupy the octahedral voids. If two $X$ atoms at the corners are replaced by $Z$ atoms,the molecular formula of the solid will be:

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