Calculate the number of unit cells in $10 \, g$ of $CsCl$ which crystallizes in a $bcc$ structure. $(CsCl = 168.5 \, amu)$

  • A
    $1.69 \times 10^{21}$
  • B
    $1.69 \times 10^{22}$
  • C
    $1.5 \times 10^{22}$
  • D
    $3.38 \times 10^{22}$

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