Which of the following pairs has the same freezing point?

  • A
    $0.01 \, m \, NaCl$ and $0.02 \, m \, MgCl_2$
  • B
    $0.02 \, m \, Na_2SO_4$ and $0.01 \, m \, Ba(NO_3)_2$
  • C
    $0.03 \, m \, KCl$ and $0.02 \, m \, Ca(NO_3)_2$
  • D
    $0.01 \, m \, K_2SO_4$ and $0.02 \, m \, NaCl$

Explore More

Similar Questions

If the freezing point of a $0.01 \ m$ aqueous solution of a cobalt $(III)$ chloride-ammonia complex (which behaves as a strong electrolyte) is $-0.0558^{\circ} C$,the number of chloride $(Cl^-)$ ions in the coordination sphere of the complex is.
$\left[ K_{f} \text{ of water } = 1.86 \ K \ kg \ mol^{-1} \right]$

What is the freezing point of a solution containing $8.1 \ g \ HBr$ in $100 \ g$ water,assuming the acid to be $90 \ \%$ ionised ($K_f$ for water $= 1.86 \ K \ kg \ mol^{-1}$)?

Difficult
View Solution

For a $0.01 \ m$ aqueous solution of $K_4[Fe(CN)_6]$,if $K_b = 0.52 \ K \ kg \ mol^{-1}$ for the solvent,then its boiling point will be ..... $^\circ C$.

Molal depression constant for a solvent is $4.0 \, K \, kg \, mol^{-1}$. The depression in the freezing point of the solvent for $0.03 \, mol \, kg^{-1}$ solution of $K_2SO_4$ is .............. $K$ (Assume complete dissociation of the electrolyte).

The Van't Hoff factor for a $0.005 \ M$ aqueous solution of $KCl$ is $1.95$. The degree of ionisation of $KCl$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo