For which of the following reactions will {K_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The relationship between ${K_p}$ and ${K_c}$ is given by the equation: ${K_p} = {K_c}{(RT)^{\Delta n_g}}$.For ${K_p} > {K_c}$,the value of ${\Delt

Vedclass · Accepted Answer

${PCl_{5(g)}} \rightleftharpoons {PCl_{3(g)}} + {Cl_{2(g)}}$

Vedclass · Answer

(C) The relationship between ${K_p}$ and ${K_c}$ is given by the equation: ${K_p} = {K_c}{(RT)^{\Delta n_g}}$.For ${K_p} > {K_c}$,the value of ${\Delta n_g}$ must be positive $({\Delta n_g} > 0)$.${\Delta n_g}$ is the difference between the number of moles of gaseous products and gaseous reactants.For option $A$: ${\Delta n_g} = 2 - (1 + 3) = -2$.For option $B$: ${\Delta n_g} = 2 - (1 + 1) = 0$.For option $C$: ${\Delta n_g} = (1 + 1) - 1 = +1$.For option $D$: ${\Delta n_g} = 2 - (2 + 1) = -1$.Since ${\Delta n_g} > 0$ only for option $C$,the correct answer is $C$.

For which of the following reactions will ${K_p} > {K_c}$?

Similar Questions

For the reaction $2SO_{2(g)} + O_{2(g)} \rightleftharpoons 2SO_{3(g)}$,which of the following equations is correct?

$A$ sample of $HI_{(g)}$ is placed in a flask at a pressure of $0.2 \ atm$. At equilibrium,the partial pressure of $HI_{(g)}$ is $0.04 \ atm$. What is $K_{p}$ for the given equilibrium?
$2 HI_{(g)} \longleftrightarrow H_{2_{(g)}} + I_{2_{(g)}}$

The value of $K_{p}$ for the reaction,$CO_{2(g)} + C_{(s)} \rightleftharpoons 2CO_{(g)}$ is $3.0$ at $1000 \ K$. If initially $P_{CO_{2}} = 0.48 \ bar$ and $P_{CO} = 0 \ bar$ and pure graphite is present,calculate the equilibrium partial pressures of $CO$ and $CO_{2}$.

For the reaction $2NO_{2(g)} \rightleftharpoons 2NO_{(g)} + O_{2(g)}$,the value of $K_c$ is $1.8 \times 10^{-6}$ at $184^{\circ}C$. Given $R = 0.083 \ L \cdot bar \cdot K^{-1} \cdot mol^{-1}$,compare $K_p$ and $K_c$ at $184^{\circ}C$.

One mole of $SO_3$ was placed in a $1 \ L$ reaction vessel at a certain temperature. The following equilibrium was established: $2SO_3 \rightleftharpoons 2SO_2 + O_2$. At equilibrium,$0.6 \ moles$ of $SO_2$ were formed. The equilibrium constant $(K_c)$ of the reaction will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module