In the equilibrium 2A_{(g)} + 3B_{(g)} rightl | vedclass

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(C) According to Le Chatelier's principle,an increase in pressure favors the direction that has a smaller number of moles of gaseous species.For the g

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Have no effect on the equilibrium

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(C) According to Le Chatelier's principle,an increase in pressure favors the direction that has a smaller number of moles of gaseous species.For the given reaction: $2A_{(g)} + 3B_{(g)} \rightleftharpoons 3C_{(g)} + 2D_{(g)}$Total moles of gaseous reactants = $2 + 3 = 5$Total moles of gaseous products = $3 + 2 = 5$Since the number of moles of gaseous reactants is equal to the number of moles of gaseous products $(\Delta n_g = 0)$,a change in pressure will have no effect on the equilibrium position.

In the equilibrium $2A_{(g)} + 3B_{(g)} \rightleftharpoons 3C_{(g)} + 2D_{(g)}$,an increase in pressure will:

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