For the reaction 2X_{(g)} + Y_{(g)} rightleft | vedclass

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(B) The given reaction is $2X_{(g)} + Y_{(g)} \rightleftharpoons 2Z_{(g)} + 80 \ kcal$.
Since the reaction is exothermic $(\Delta H < 0)$,accordin

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$1000 \ atm$ and $100 \ ^\circ C$

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(B) The given reaction is $2X_{(g)} + Y_{(g)} \rightleftharpoons 2Z_{(g)} + 80 \ kcal$.
Since the reaction is exothermic $(\Delta H < 0)$,according to Le Chatelier's principle,a lower temperature will shift the equilibrium in the forward direction to produce more $Z$.
For pressure,the number of moles of gaseous reactants is $2 + 1 = 3$,and the number of moles of gaseous products is $2$.
Since the number of moles decreases in the forward direction,increasing the pressure will shift the equilibrium in the forward direction to produce more $Z$.
Therefore,high pressure and low temperature are the ideal conditions.
Comparing the given options,$1000 \ atm$ (high pressure) and $100 \ ^\circ C$ (lowest temperature among options) will yield the maximum amount of $Z$.

For the reaction $2X_{(g)} + Y_{(g)} \rightleftharpoons 2Z_{(g)} + 80 \ kcal$,which conditions of temperature and pressure will yield more $Z$ at equilibrium?

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