Sulfanilic acid is a/an ....

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Question

(C) Sulfanilic acid $(NH_2-C_6H_4-SO_3H)$ exists as a zwitterion in aqueous solution,where the acidic $-SO_3H$ group donates a proton to the basic $-N

Vedclass · Accepted Answer

Both $(A)$ and $(B)$

Vedclass · Answer

(C) Sulfanilic acid $(NH_2-C_6H_4-SO_3H)$ exists as a zwitterion in aqueous solution,where the acidic $-SO_3H$ group donates a proton to the basic $-NH_2$ group to form $^+NH_3-C_6H_4-SO_3^-$. Due to the presence of the $-SO_3H$ group,it acts as an Arrhenius acid by increasing the concentration of $H^+$ ions in water. Additionally,the $-NH_2$ group contains a lone pair of electrons on the nitrogen atom,which allows it to act as a Lewis base by donating this electron pair. Therefore,it exhibits both characteristics.

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