At what concentration of 0.2 M CH_3COOH will | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a weak acid,the degree of dissociation $\alpha$ is given by $\alpha = \sqrt{\frac{K_a}{C}}$.Let the initial concentration be $C_1 = 0.2 \ M$ a

Vedclass · Accepted Answer

$0.05$

Vedclass · Answer

(A) For a weak acid,the degree of dissociation $\alpha$ is given by $\alpha = \sqrt{\frac{K_a}{C}}$.Let the initial concentration be $C_1 = 0.2 \ M$ and the initial degree of dissociation be $\alpha_1$.Then $\alpha_1 = \sqrt{\frac{K_a}{C_1}}$.We want the new degree of dissociation $\alpha_2 = 2\alpha_1$.So,$\alpha_2 = \sqrt{\frac{K_a}{C_2}} = 2 \sqrt{\frac{K_a}{C_1}}$.Squaring both sides,we get $\frac{K_a}{C_2} = 4 \frac{K_a}{C_1}$.This simplifies to $C_2 = \frac{C_1}{4}$.Substituting $C_1 = 0.2 \ M$,we get $C_2 = \frac{0.2}{4} = 0.05 \ M$.

At what concentration of $0.2 \ M$ $CH_3COOH$ will its degree of dissociation become double (in $M$)? (Given: $K_a = 1.8 \times 10^{-5}$ for $CH_3COOH$)

Similar Questions

The ionization constant of acetic acid is $1.74 \times 10^{-5}$. Calculate the degree of dissociation of acetic acid in its $0.05 \ M$ solution. Calculate the concentration of acetate ion in the solution and its $pH$.

The $K_a$ of monobasic acid $A, B$ and $C$ are $10^{-6}, 10^{-8}$ and $10^{-10}$ respectively. The concentrations of $A, B$ and $C$ are respectively $0.1 \ M, 0.01 \ M$ and $0.001 \ M$. Which of the following is correct for $pOH$ of $A, B$ and $C$?

For two acids $A$ and $B$,the values of $pK_{a1} = 1.2$ and $pK_{a2} = 2.8$ are given. Which of the following is correct?

$A$ monoprotic acid in a $0.1 \ M$ solution ionizes to $0.001 \%$. Its ionisation constant is

Calculate the value of the dissociation constant $(K_b)$ of a weak monoacidic base if it dissociates to $2 \%$ in a $0.1 \ M$ solution.

Vedclass Test Series

Exam Paper Generator

Online Exam Module