Calculate the enthalpy change in kJ for the r | vedclass

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(B) Given reactions:$(i) \ C_{(graphite)} + O_{2(g)} 	o CO_{2(g)} \quad \Delta H_1 = -393.5 \ kJ$$(ii) \ C_2H_{4(g)} + 3O_{2(g)} 	o 2CO_{2(g)} + 2H_

Vedclass · Accepted Answer

$52.3$

Vedclass · Answer

(B) Given reactions:$(i) \ C_{(graphite)} + O_{2(g)} 	o CO_{2(g)} \quad \Delta H_1 = -393.5 \ kJ$$(ii) \ C_2H_{4(g)} + 3O_{2(g)} 	o 2CO_{2(g)} + 2H_2O_{(l)} \quad \Delta H_2 = -1410.9 \ kJ$$(iii) \ H_{2(g)} + 1/2O_{2(g)} 	o H_2O_{(l)} \quad \Delta H_3 = -285.8 \ kJ$Target reaction: $2C_{(graphite)} + 2H_{2(g)} 	o C_2H_{4(g)}$To obtain the target reaction,perform: $2 	imes (i) + 2 	imes (iii) - (ii)$$\Delta H = 2 	imes (-393.5) + 2 	imes (-285.8) - (-1410.9)$$\Delta H = -787.0 - 571.6 + 1410.9$$\Delta H = -1358.6 + 1410.9 = 52.3 \ kJ$

Similar Questions

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