Determine the hybridization of the sulfur ato | vedclass

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(B) The hybridization of an atom can be calculated using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electrons o

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$sp^2$

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(B) The hybridization of an atom can be calculated using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $SO_2$,the central atom is sulfur $(S)$.Valence electrons of $S = 6$.Number of monovalent atoms ($O$ is divalent) = $0$.$H = \frac{1}{2} (6 + 0 - 0 + 0) = 3$.$A$ steric number of $3$ corresponds to $sp^2$ hybridization.In $SO_2$,sulfur has one lone pair and two sigma bonds,resulting in $sp^2$ hybridization.

Determine the hybridization of the sulfur atom in $SO_2$.

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