F_2 is a stronger oxidizing agent than Br_2 d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The oxidizing power of a halogen depends on the standard electrode potential $(E^\circ)$.$F_2$ has a very high positive standard electrode potenti

Vedclass · Accepted Answer

Small size of fluorine

Vedclass · Answer

(A) The oxidizing power of a halogen depends on the standard electrode potential $(E^\circ)$.$F_2$ has a very high positive standard electrode potential $(+2.87 \ V)$ compared to $Br_2$ $(+1.09 \ V)$.This is primarily due to the low bond dissociation enthalpy of the $F-F$ bond and the high hydration enthalpy of the $F^-$ ion.However,the small size of the fluorine atom leads to high electron-electron repulsion in the $F^-$ ion,which is a significant factor in its thermodynamic properties,but the overall oxidizing strength is governed by the sum of atomization,ionization/electron gain,and hydration energies.Among the given options,the small size of the fluorine atom is the fundamental reason for its unique properties,including its high oxidizing power.

$F_2$ is a stronger oxidizing agent than $Br_2$ due to..........

Similar Questions

Which one of the following orders is not in accordance with the property stated against it?

Which of the following oxidation states are exhibited by iodine?

Discuss the anomalous behaviour of fluorine.

When cold and dilute $NaOH$ reacts with $Cl_2$, which of the following is formed?

Which one among the following non-metals is liquid at $25 ^\circ C$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module