How can the charge distribution in iodine mon | vedclass

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(B) Iodine $(I)$ has a lower electronegativity $(2.66)$ compared to Chlorine ($Cl$,$3.16$). Due to this difference in electronegativity,the shared pai

Vedclass · Accepted Answer

$I^{\delta+}Cl^{\delta-}$

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(B) Iodine $(I)$ has a lower electronegativity $(2.66)$ compared to Chlorine ($Cl$,$3.16$). Due to this difference in electronegativity,the shared pair of electrons in the $I-Cl$ bond is shifted towards the more electronegative Chlorine atom. This results in the development of a partial negative charge $(\delta-)$ on the Chlorine atom and a partial positive charge $(\delta+)$ on the Iodine atom. Therefore,the charge distribution is represented as $I^{\delta+}Cl^{\delta-}$.

How can the charge distribution in iodine monochloride $(ICl)$ be represented?

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