Which of the following molecules is planar?

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(B) To determine the geometry of the given $Xe$ compounds,we look at their hybridization and lone pairs:$1$. $XeO_4$: $sp^3$ hybridization,tetrahedral

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$XeF_4$

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(B) To determine the geometry of the given $Xe$ compounds,we look at their hybridization and lone pairs:$1$. $XeO_4$: $sp^3$ hybridization,tetrahedral geometry (non-planar).$2$. $XeF_4$: $sp^3d^2$ hybridization with $2$ lone pairs,square planar geometry (planar).$3$. $XeOF_4$: $sp^3d^2$ hybridization with $1$ lone pair,square pyramidal geometry (non-planar).$4$. $XeO_3$: $sp^3$ hybridization with $1$ lone pair,pyramidal geometry (non-planar).Therefore,$XeF_4$ is the only planar molecule.

Column-$I$	Column-$II$
$(a) XeF_6$	$(i) \text{ Distorted Octahedral}$
$(b) XeO_3$	$(ii) \text{ Square planar}$
$(c) XeOF_4$	$(iii) \text{ Pyramidal}$
$(d) XeF_4$	$(iv) \text{ Square pyramidal}$

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