The electronic configuration of a metal M is | vedclass

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(B) The electronic configuration of metal $M$ is $1s^2 \, 2s^2 \, 2p^6 \, 3s^1$. This indicates that the metal has $1$ valence electron in its outermo

Vedclass · Accepted Answer

$M_2O$

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(B) The electronic configuration of metal $M$ is $1s^2 \, 2s^2 \, 2p^6 \, 3s^1$. This indicates that the metal has $1$ valence electron in its outermost shell $(3s^1)$. Therefore,the valency of the metal $M$ is $+1$. Oxygen $(O)$ typically has a valency of $-2$. To form a neutral oxide,the charges must balance: $2 	imes (+1) + 1 	imes (-2) = 0$. Thus,the formula of the oxide is $M_2O$.

The electronic configuration of a metal $M$ is $1s^2 \, 2s^2 \, 2p^6 \, 3s^1$. What will be the formula of its oxide?

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