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(C) The chemical $A$ is calcium hydroxide,$Ca(OH)_2$ (slaked lime).$1$. It is used to remove temporary hardness of water: $Ca(HCO_3)_2 + Ca(OH)_2 \rig

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$Ca(OH)_2$

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(C) The chemical $A$ is calcium hydroxide,$Ca(OH)_2$ (slaked lime).$1$. It is used to remove temporary hardness of water: $Ca(HCO_3)_2 + Ca(OH)_2 \rightarrow 2CaCO_3 \downarrow + 2H_2O$.$2$. It reacts with sodium carbonate to produce caustic soda $(NaOH)$: $Ca(OH)_2 + Na_2CO_3 \rightarrow CaCO_3 \downarrow + 2NaOH$.$3$. When $CO_2$ is passed through lime water $(Ca(OH)_2)$,it turns milky due to the formation of calcium carbonate: $Ca(OH)_2 + CO_2 \rightarrow CaCO_3 \downarrow + H_2O$.

Chemical $A$ is used for the removal of temporary hardness of water. Compound $A$ reacts with $Na_2CO_3$ to produce caustic soda. When $CO_2$ gas is passed through $A$,it turns milky. What is the chemical formula of $A$?

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