Heating a solid compound X produces CO_2 gas | vedclass

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(B) The reactions are as follows:$1$. Heating $X$ $(CaCO_3)$: $CaCO_3 \xrightarrow{\Delta} CaO + CO_2 \uparrow$$2$. Residue $(CaO)$ + water $(H_2O)$:

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$CaCO_3$

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(B) The reactions are as follows:$1$. Heating $X$ $(CaCO_3)$: $CaCO_3 \xrightarrow{\Delta} CaO + CO_2 \uparrow$$2$. Residue $(CaO)$ + water $(H_2O)$: $CaO + H_2O \rightarrow Ca(OH)_2$ $(Y)$$3$. Passing excess $CO_2$ through $Y$ $(Ca(OH)_2)$: $Ca(OH)_2 + 2CO_2 \rightarrow Ca(HCO_3)_2$ $(Z)$$4$. Boiling $Z$ $(Ca(HCO_3)_2)$: $Ca(HCO_3)_2 \xrightarrow{\Delta} CaCO_3 + H_2O + CO_2 \uparrow$ (Regenerates $X$)Therefore,$X$ is $CaCO_3$.

Heating a solid compound $X$ produces $CO_2$ gas and a residue. Adding water to this residue produces compound $Y$. Passing excess $CO_2$ gas through a solution of $Y$ produces a clear solution $Z$. Boiling $Z$ regenerates compound $X$. What is compound $X$?

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