The $Gold \ Number$ indicates:
- AThe amount of gold present in the colloid.
- BThe amount of gold required to break the colloid.
- CThe amount of protective colloid required to prevent coagulation of $10 \ mL$ of gold sol by $1 \ mL$ of $10\% \ NaCl$ solution.
- DNone of the above.
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Similar Questions
Match List-$I$ with List-$II$.
List-$I$ List-$II$ $A$. Negatively charged sol $I$. $Fe_{2}O_{3} \cdot xH_{2}O$ $B$. Macromolecular colloid $II$. $CdS$ sol $C$. Positively charged sol $III$. Starch $D$. Cheese $IV$. $A$ gel
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
| $A$. Negatively charged sol | $I$. $Fe_{2}O_{3} \cdot xH_{2}O$ |
| $B$. Macromolecular colloid | $II$. $CdS$ sol |
| $C$. Positively charged sol | $III$. Starch |
| $D$. Cheese | $IV$. $A$ gel |
Choose the correct answer from the options given below:
The charge on $As_2S_3$ sol is due to the adsorbed
Medium
View SolutionIn soap lather,the dispersed phase and dispersion medium are respectively ....
Easy
View SolutionThe coagulation values in millimoles per litre of the electrolytes used for the coagulation of $As_2S_3$ are given below:
$I$. $(NaCl) = 52,$
$II$. $(BaCl_2) = 0.69,$
$III$. $(MgSO_4) = 0.22$
The correct order of their coagulating power is:
$I$. $(NaCl) = 52,$
$II$. $(BaCl_2) = 0.69,$
$III$. $(MgSO_4) = 0.22$
The correct order of their coagulating power is:
MediumNEET 2016
View SolutionThe gold numbers of protective colloids $A, B, C$,and $D$ are $0.04, 0.004, 10$,and $40$ respectively. The order of their protective power is:
Medium
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