100 mL of 0.6 M acetic acid is shaken with | vedclass

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(B) Initial moles of acetic acid $= M 	imes V(L) = 0.6 	imes 0.1 = 0.06 \ mol$. Final moles of acetic acid $= 0.5 	imes 0.1 = 0.05 \ mol$. Moles ad

Vedclass · Accepted Answer

$0.3$

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(B) Initial moles of acetic acid $= M 	imes V(L) = 0.6 	imes 0.1 = 0.06 \ mol$. Final moles of acetic acid $= 0.5 	imes 0.1 = 0.05 \ mol$. Moles adsorbed $= 0.06 - 0.05 = 0.01 \ mol$. Molar mass of acetic acid $(CH_3COOH) = 60 \ g/mol$. Mass of acetic acid adsorbed on $2 \ g$ of charcoal $= 0.01 \ mol 	imes 60 \ g/mol = 0.6 \ g$. Mass of acetic acid adsorbed per gram of charcoal $= \frac{0.6 \ g}{2 \ g} = 0.3 \ g$.

$100 \ mL$ of $0.6 \ M$ acetic acid is shaken with $2 \ g$ of activated charcoal. After adsorption,the final concentration of the solution becomes $0.5 \ M$. The amount of acetic acid adsorbed per gram of carbon is .......... $g$.

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