How many structural isomers of {C_5}{H_{11}}O | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine the number of primary alcohols with the molecular formula ${C_5}{H_{11}}OH$, we identify structures where the $-OH$ group is attached

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) To determine the number of primary alcohols with the molecular formula ${C_5}{H_{11}}OH$, we identify structures where the $-OH$ group is attached to a primary carbon atom (a carbon atom bonded to only one other carbon atom).$1$. $CH_3-CH_2-CH_2-CH_2-CH_2-OH$ (Pentan$-1$-ol)$2$. $CH_3-CH_2-CH(CH_3)-CH_2-OH$ ($2$-Methylbutan$-1$-ol)$3$. $CH_3-CH(CH_3)-CH_2-CH_2-OH$ ($3$-Methylbutan$-1$-ol)$4$. $(CH_3)_3C-CH_2-OH$ ($2,2$-Dimethylpropan$-1$-ol)There are a total of $4$ structural primary alcohol isomers.

How many structural isomers of ${C_5}{H_{11}}OH$ are primary alcohols?

Similar Questions

The steps involved in the conversion of propan$-2-$ol to propan$-1-$ol are in the order

The strongest acid among the following is:

When vapours of a secondary alcohol are passed over heated copper at $573 \; K$,the product formed is:

Iodoform can be prepared from all,except

$8.8 \ g$ of monohydric alcohol added to ethyl magnesium iodide in ether liberates $2240 \ cm^3$ of ethane at $STP$. This monohydric alcohol when oxidized using pyridinium chlorochromate $(PCC)$,forms a carbonyl compound that answers the silver mirror test (Tollen's test). The monohydric alcohol is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module