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(A) The oxidation of primary alcohols like ethyl alcohol $(CH_3CH_2OH)$ with strong oxidizing agents such as acidic $K_2Cr_2O_7$ proceeds in two steps

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Acetic acid

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(A) The oxidation of primary alcohols like ethyl alcohol $(CH_3CH_2OH)$ with strong oxidizing agents such as acidic $K_2Cr_2O_7$ proceeds in two steps.First,the alcohol is oxidized to an aldehyde,$CH_3CHO$ (acetaldehyde).Second,the aldehyde is further oxidized to a carboxylic acid,$CH_3COOH$ (acetic acid).Under standard laboratory conditions with excess oxidizing agent,the final stable product is acetic acid.

What product is formed when ethyl alcohol is oxidized with $K_2Cr_2O_7$?

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