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(C) The conversion of propene $(CH_3-CH=CH_2)$ to propan-$1$-ol $(CH_3-CH_2-CH_2-OH)$ is an anti-Markovnikov hydration reaction.This transformation is

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$B_2H_6$ followed by $H_2O_2 / OH^-$

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(C) The conversion of propene $(CH_3-CH=CH_2)$ to propan-$1$-ol $(CH_3-CH_2-CH_2-OH)$ is an anti-Markovnikov hydration reaction.This transformation is achieved via hydroboration-oxidation.In the first step,diborane $(B_2H_6)$ adds across the double bond to form an alkyl borane.In the second step,oxidation with hydrogen peroxide $(H_2O_2)$ in the presence of an aqueous base $(OH^-)$ yields the primary alcohol,propan-$1$-ol.Option $A$ and $B$ follow Markovnikov's rule,resulting in propan-$2$-ol.

Which of the following reagents can be used to convert propene into propan-$1$-ol?

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