(CH_3)_2CHOH xrightarrow{dil. , [O]} X xright | vedclass

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(B) $1$. The starting material is isopropyl alcohol $(CH_3)_2CHOH$. $2$. Oxidation of a secondary alcohol with dilute oxidizing agents (like $KMnO_4$

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Tertiary butyl alcohol

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(B) $1$. The starting material is isopropyl alcohol $(CH_3)_2CHOH$. $2$. Oxidation of a secondary alcohol with dilute oxidizing agents (like $KMnO_4$ or $CrO_3$) yields a ketone,which is acetone $(CH_3COCH_3)$. Thus,$X = CH_3COCH_3$. $3$. The reaction of acetone with methylmagnesium bromide $(CH_3MgBr)$ followed by hydrolysis is a Grignard reaction. $4$. $CH_3COCH_3 + CH_3MgBr \rightarrow (CH_3)_3COMgBr$. $5$. Subsequent hydrolysis of $(CH_3)_3COMgBr$ yields tertiary butyl alcohol $(CH_3)_3COH$. Thus,$Y = (CH_3)_3COH$.

$(CH_3)_2CHOH$ $\xrightarrow{dil. \, [O]} X$ $\xrightarrow[(ii) \, H_2O]{(i) \, CH_3MgBr} Y$. What is $Y$ here?

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