When ethanol is reacted with PCl_5,it gives A | vedclass

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(C) The reaction of ethanol $(C_2H_5OH)$ with $PCl_5$ is a standard substitution reaction:$C_2H_5OH + PCl_5 \rightarrow C_2H_5Cl (A) + POCl_3 + HCl$Th

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$C_2H_5Cl$ and $C_2H_5NO_2$

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(C) The reaction of ethanol $(C_2H_5OH)$ with $PCl_5$ is a standard substitution reaction:$C_2H_5OH + PCl_5 \rightarrow C_2H_5Cl (A) + POCl_3 + HCl$Thus,$A$ is ethyl chloride $(C_2H_5Cl)$.Next,the reaction of ethyl chloride $(C_2H_5Cl)$ with silver nitrite $(AgNO_2)$ is a nucleophilic substitution reaction:$C_2H_5Cl + AgNO_2 \rightarrow C_2H_5NO_2 (B) + AgCl$Thus,$B$ is nitroethane $(C_2H_5NO_2)$.Therefore,the correct pair is $A = C_2H_5Cl$ and $B = C_2H_5NO_2$.

When ethanol is reacted with $PCl_5$,it gives $A$,$POCl_3$,and $HCl$. The reaction of $A$ with silver nitrite $(AgNO_2)$ gives the major product $(B)$ and $AgCl$. What are $A$ and $B$ respectively?

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