What is X in the following reaction?C_2H_5OC_ | vedclass

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(A) The reaction of diethyl ether with excess of concentrated $HI$ in the presence of red phosphorus at $423 \ K$ is a reduction reaction.$C_2H_5OC_2H

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Ethane

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(A) The reaction of diethyl ether with excess of concentrated $HI$ in the presence of red phosphorus at $423 \ K$ is a reduction reaction.$C_2H_5OC_2H_5 + 2HI \xrightarrow{Red \ P, 423 \ K} 2C_2H_5I + H_2O$Further,the ethyl iodide formed is reduced by $HI$ in the presence of red phosphorus:$2C_2H_5I + 2HI \xrightarrow{Red \ P} 2C_2H_6 + 2I_2$Combining these steps,the overall reaction is:$C_2H_5OC_2H_5 + 4[H] \xrightarrow{Red \ P + HI} 2C_2H_6 + H_2O$Comparing this with the given equation,$2X = 2C_2H_6$,so $X = C_2H_6$ (Ethane).

What is $X$ in the following reaction?
$C_2H_5OC_2H_5 + 4[H] \xrightarrow{Red \ P + HI} 2X + H_2O$

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What is $X$ in the following reaction?$C_2H_5OC_2H_5 + 4[H] \xrightarrow{Red \ P + HI} 2X + H_2O$