Assertion : A tennis ball bounces higher on h | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the tennis ball bounce with an initial velocity $u$. It will rise to a height $h$ where its final velocity becomes $0$. Using the equation of

Vedclass · Accepted Answer

If the $Assertion$ is correct but $Reason$ is incorrect.

Vedclass · Answer

(C) Let the tennis ball bounce with an initial velocity $u$. It will rise to a height $h$ where its final velocity becomes $0$. Using the equation of motion $v^2 - u^2 = 2as$,we get:$0^2 - u^2 = 2(-g')h$,where $g'$ is the acceleration due to gravity on the hill.Therefore,$h = \frac{u^2}{2g'}$.Since the acceleration due to gravity on the hill $(g')$ is less than that on the surface of the earth $(g)$ due to the increase in altitude,the height $h$ will be greater on the hill.Thus,the $Assertion$ is correct,but the $Reason$ is incorrect because $g'$ is actually less than $g$.

$Assertion$ : $A$ tennis ball bounces higher on hills than in plains.
$Reason$ : Acceleration due to gravity on the hill is greater than that on the surface of earth.

Similar Questions

The magnitudes of the gravitational field at distances $r_1$ and $r_2$ from the center of a uniform sphere of radius $R$ and mass $M$ are $F_1$ and $F_2$ respectively. Then:

How much is the radius of the Earth at the equator greater than the radius at the poles?

When a body is taken from the pole to the equator,its weight:

$g_e$ and $g_p$ denote the acceleration due to gravity on the surface of the Earth and another planet whose mass and radius are twice that of the Earth. Then:

$Assertion$ : In a free fall,the weight of a body becomes effectively zero.
$Reason$ : The acceleration due to gravity acting on a body in free fall is zero.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Assertion$ : $A$ tennis ball bounces higher on hills than in plains.$Reason$ : Acceleration due to gravity on the hill is greater than that on the surface of earth.