$Ge(II)$ compounds are powerful reducing agents whereas $Pb(IV)$ compounds are strong oxidants. This can be attributed to:
- A$Pb$ is more electropositive than $Ge$
- BIonization potential of lead is less than that of $Ge$
- CIonic radii of $Pb^{2+}$ and $Pb^{4+}$ are larger than those of $Ge^{2+}$ and $Ge^{4+}$
- DMore pronounced inert pair effect in lead than in $Ge$
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View SolutionWhich among the following group $15$ elements does not exhibit allotropy?
What are the number of $P - O - P$ bridges in phosphorus pentoxide and phosphorus trioxide,respectively?
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View SolutionMatch the reactions (in the given stoichiometry of the reactants) in List-$I$ with one of their products given in List-$II$ and choose the correct option.
List-$I$ List-$II$ $A. P_2 O_3 + 3 H_2 O \rightarrow$ $1. P(O)(OCH_3)Cl_2$ $B. P_4 + 3 NaOH + 3 H_2 O \rightarrow$ $2. H_3 PO_3$ $C. PCl_5 + CH_3 COOH \rightarrow$ $3. PH_3$ $D. H_3 PO_2 + 2 H_2 O + 4 AgNO_3 \rightarrow$ $4. CH_3 COCl$ $5. H_3 PO_4$
| List-$I$ | List-$II$ |
| $A. P_2 O_3 + 3 H_2 O \rightarrow$ | $1. P(O)(OCH_3)Cl_2$ |
| $B. P_4 + 3 NaOH + 3 H_2 O \rightarrow$ | $2. H_3 PO_3$ |
| $C. PCl_5 + CH_3 COOH \rightarrow$ | $3. PH_3$ |
| $D. H_3 PO_2 + 2 H_2 O + 4 AgNO_3 \rightarrow$ | $4. CH_3 COCl$ |
| $5. H_3 PO_4$ |
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