$SnCl_2$ gives a precipitate with a solution of $HgCl_2$. In this process $HgCl_2$ is

  • A
    Reduced
  • B
    Oxidised
  • C
    Converted into a complex compound containing both $Sn$ and $Hg$
  • D
    Converted into a chloro complex of $Hg$

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