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(D) The chemical reactions are as follows:$(a)$ $Zn(s) + 2HCl(aq) \longrightarrow ZnCl_{2}(aq) + H_{2}(g)$$(b)$ $Zn(s) + 2NaOH(aq) + 2H_{2}O(l) \longr

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$1 : 1$

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(D) The chemical reactions are as follows:$(a)$ $Zn(s) + 2HCl(aq) \longrightarrow ZnCl_{2}(aq) + H_{2}(g)$$(b)$ $Zn(s) + 2NaOH(aq) + 2H_{2}O(l) \longrightarrow Na_{2}[Zn(OH)_{4}](aq) + H_{2}(g)$From the stoichiometry of both balanced equations,$1 \ mole$ of $Zn$ produces $1 \ mole$ of $H_{2}$ gas in both cases.Since the amount of $Zn$ $(5 \ g)$ is the same in both reactions,the number of moles of $H_{2}$ produced will be identical.Therefore,the ratio of the volumes of $H_{2}$ evolved is $1 : 1$.

$5 \ g$ of zinc is treated separately with an excess of
$(a)$ dilute hydrochloric acid and
$(b)$ aqueous sodium hydroxide.
The ratio of the volumes of $H_{2}$ evolved in these two reactions is:

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$5 \ g$ of zinc is treated separately with an excess of$(a)$ dilute hydrochloric acid and$(b)$ aqueous sodium hydroxide.The ratio of the volumes of $H_{2}$ evolved in these two reactions is: