$H_2S$ acts only as a reducing agent while $SO_2$ can act both as a reducing and oxidizing agent because
- A$S$ in $H_2S$ has $-2$ oxidation state
- B$S$ in $SO_2$ has oxidation state $+4$
- CHydrogen in $H_2S$ is more electropositive than oxygen
- DBoth $(a)$ and $(b)$
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