A block P of mass m is placed on a frictionle | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When two blocks perform simple harmonic motion together,the system acts as a single body of mass $2m$ attached to a spring of constant $k$.The acc

Vedclass · Accepted Answer

$\frac{kA}{2}$

Vedclass · Answer

(B) When two blocks perform simple harmonic motion together,the system acts as a single body of mass $2m$ attached to a spring of constant $k$.The acceleration of the system at any displacement $x$ is given by $a = -\omega^2 x$,where $\omega^2 = \frac{k}{2m}$.At the extreme position,the displacement is $x = A$,so the magnitude of acceleration is $a_{max} = \omega^2 A = \frac{k}{2m} A = \frac{kA}{2m}$.The friction force $f$ acting on block $P$ provides the necessary acceleration to it. Since block $P$ has mass $m$,the friction force is $f = m \cdot a$.At the extreme position,the friction force reaches its maximum value: $f_{max} = m \cdot a_{max} = m \left( \frac{kA}{2m} \right) = \frac{kA}{2}$.

Similar Questions

$A$ particle of mass $200\,g$ executes a simple harmonic motion. The restoring force is provided by a spring of spring constant $80\,N/m$. The time period is .... $\sec$

Three masses $500 \ g$,$300 \ g$,and $100 \ g$ are suspended at the end of a spring as shown in the figure and are in equilibrium. When the $500 \ g$ mass is removed,the system oscillates with a period of $2 \ s$. When the $300 \ g$ mass is also removed,it will oscillate with a period of (in $s$)

Two masses $m_1$ and $m_2$ are suspended together by a massless spring of constant $K$. When the masses are in equilibrium,$m_1$ is removed without disturbing the system. The amplitude of oscillations is

Vedclass Test Series

Exam Paper Generator

Online Exam Module