A = {1, 2, 3, 5} and B = {4, 6, 9}. Define a | vedclass

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(A) Given sets are $A = \{1, 2, 3, 5\}$ and $B = \{4, 6, 9\}$.
The relation $R$ is defined as the set of all ordered pairs $(x, y)$ such that $|x - y

Vedclass · Accepted Answer

$R = \{(1, 4), (1, 6), (2, 9), (3, 4), (3, 6), (5, 4), (5, 6)\}$

Vedclass · Answer

(A) Given sets are $A = \{1, 2, 3, 5\}$ and $B = \{4, 6, 9\}$.
The relation $R$ is defined as the set of all ordered pairs $(x, y)$ such that $|x - y|$ is odd,where $x \in A$ and $y \in B$.
Checking each pair:
For $x = 1$: $|1 - 4| = 3$ (odd),$|1 - 6| = 5$ (odd),$|1 - 9| = 8$ (even). So,$(1, 4)$ and $(1, 6) \in R$.
For $x = 2$: $|2 - 4| = 2$ (even),$|2 - 6| = 4$ (even),$|2 - 9| = 7$ (odd). So,$(2, 9) \in R$.
For $x = 3$: $|3 - 4| = 1$ (odd),$|3 - 6| = 3$ (odd),$|3 - 9| = 6$ (even). So,$(3, 4)$ and $(3, 6) \in R$.
For $x = 5$: $|5 - 4| = 1$ (odd),$|5 - 6| = 1$ (odd),$|5 - 9| = 4$ (even). So,$(5, 4)$ and $(5, 6) \in R$.
Thus,$R = \{(1, 4), (1, 6), (2, 9), (3, 4), (3, 6), (5, 4), (5, 6)\}$.

$A = \{1, 2, 3, 5\}$ and $B = \{4, 6, 9\}$. Define a relation $R$ from $A$ to $B$ by $R = \{(x, y) : \text{the difference between } x \text{ and } y \text{ is odd}; x \in A, y \in B\}$. Write $R$ in roster form.

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