5.74 ; g of a substance occupies 1.2 ; cm^3. | vedclass

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(B) The mass is $5.74 \; g$,which has $3$ significant figures.The volume is $1.2 \; cm^3$,which has $2$ significant figures.According to the rules of

Vedclass · Accepted Answer

$4.8$

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(B) The mass is $5.74 \; g$,which has $3$ significant figures.The volume is $1.2 \; cm^3$,which has $2$ significant figures.According to the rules of significant figures in division,the result should be reported to the same number of significant figures as the measurement with the fewest significant figures.Therefore,the result must be rounded to $2$ significant figures.$	ext{Density} = \frac{	ext{Mass}}{	ext{Volume}} = \frac{5.74 \; g}{1.2 \; cm^3} \approx 4.7833 \; g/cm^3$.Rounding $4.7833$ to $2$ significant figures gives $4.8 \; g/cm^3$.

$5.74 \; g$ of a substance occupies $1.2 \; cm^3$. Express its density (in $g/cm^3$) by keeping the significant figures in view.

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