3 and 6 electrons are present in the outermos | vedclass

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(A) The element $A$ has $3$ valence electrons,so it will lose $3$ electrons to form an ion with a charge of $+3$ $(A^{3+})$.The element $B$ has $6$ va

Vedclass · Accepted Answer

$A_2B_3$

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(A) The element $A$ has $3$ valence electrons,so it will lose $3$ electrons to form an ion with a charge of $+3$ $(A^{3+})$.The element $B$ has $6$ valence electrons,so it will gain $2$ electrons to complete its octet,forming an ion with a charge of $-2$ $(B^{2-})$.To form a neutral compound,the total positive charge must equal the total negative charge.Using the criss-cross method: $A^{3+}$ and $B^{2-}$ combine to form $A_2B_3$.

$3$ and $6$ electrons are present in the outermost orbit of $A$ and $B$ respectively. The chemical formula of its compound will be

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