NaOH is manufactured by the electrolysis of a | vedclass

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(A) The electrolysis of brine ($NaCl$ solution) is known as the Chlor-alkali process.During this process,$NaCl$ dissociates into $Na^+$ and $Cl^-$ ion

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$Cl_2$ and $H_2$

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(A) The electrolysis of brine ($NaCl$ solution) is known as the Chlor-alkali process.During this process,$NaCl$ dissociates into $Na^+$ and $Cl^-$ ions.At the cathode,water is reduced to produce $H_2$ gas and $OH^-$ ions: $2H_2O + 2e^- 	o H_2 + 2OH^-$.At the anode,$Cl^-$ ions are oxidized to produce $Cl_2$ gas: $2Cl^- 	o Cl_2 + 2e^-$.The $Na^+$ ions combine with $OH^-$ ions to form $NaOH$.The overall reaction is: $2NaCl(aq) + 2H_2O(l) 	o 2NaOH(aq) + Cl_2(g) + H_2(g)$.

$NaOH$ is manufactured by the electrolysis of a brine solution. The products of the reaction are:

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