0.3780 , g of an organic chloro compound gave | vedclass

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(A) Given that,Mass of organic compound $= 0.3780 \, g$.Mass of $AgCl$ formed $= 0.5740 \, g$.$1 \, mol$ of $AgCl$ $(143.32 \, g/mol)$ contains $1 \,

Vedclass · Accepted Answer

$37.59$

Vedclass · Answer

(A) Given that,Mass of organic compound $= 0.3780 \, g$.Mass of $AgCl$ formed $= 0.5740 \, g$.$1 \, mol$ of $AgCl$ $(143.32 \, g/mol)$ contains $1 \, mol$ of $Cl$ $(35.5 \, g/mol)$.Mass of chlorine in $0.5740 \, g$ of $AgCl = \frac{35.5 	imes 0.5740}{143.32} = 0.1421 \, g$.Percentage of chlorine $= \frac{	ext{Mass of chlorine}}{	ext{Mass of organic compound}} 	imes 100$.Percentage of chlorine $= \frac{0.1421}{0.3780} 	imes 100 = 37.59 \%$.Hence,the percentage of chlorine present in the compound is $37.59 \%$.

$0.3780 \, g$ of an organic chloro compound gave $0.5740 \, g$ of silver chloride in Carius estimation. Calculate the percentage of chlorine present in the compound. (in $\%$)

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