If the momentum of an object is doubled,what | vedclass

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(C) The kinetic energy $K$ of an object with mass $m$ and momentum $p$ is given by $K = \frac{p^2}{2m}$.If the momentum is doubled,the new momentum $p

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$300$

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(C) The kinetic energy $K$ of an object with mass $m$ and momentum $p$ is given by $K = \frac{p^2}{2m}$.If the momentum is doubled,the new momentum $p' = 2p$.The new kinetic energy $K'$ is given by $K' = \frac{(p')^2}{2m} = \frac{(2p)^2}{2m} = \frac{4p^2}{2m} = 4K$.The increase in kinetic energy is $\Delta K = K' - K = 4K - K = 3K$.The percentage increase in kinetic energy is $\frac{\Delta K}{K} 	imes 100 = \frac{3K}{K} 	imes 100 = 300\%$.

If the momentum of an object is doubled,what is the percentage increase in its kinetic energy (in $\%$)?

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