$0.1 \, Pa = \dots \, Nm^{-2} = \dots \, \text{dyne} \, cm^{-2}$.

(0.1, 1) $1$. We know that $1 \, Pa = 1 \, N/m^2$. Therefore,$0.1 \, Pa = 0.1 \, Nm^{-2}$.
$2$. To convert $Nm^{-2}$ to $\text{dyne} \, cm^{-2}$,we use the conversion factors: $1 \, N = 10^5 \, \text{dyne}$ and $1 \, m^2 = (10^2 \, cm)^2 = 10^4 \, cm^2$.
$3$. Thus,$1 \, Nm^{-2} = \frac{10^5 \, \text{dyne}}{10^4 \, cm^2} = 10 \, \text{dyne} \, cm^{-2}$.
$4$. Therefore,$0.1 \, Nm^{-2} = 0.1 \times 10 \, \text{dyne} \, cm^{-2} = 1 \, \text{dyne} \, cm^{-2}$.
$5$. The final result is $0.1 \, Pa = 0.1 \, Nm^{-2} = 1 \, \text{dyne} \, cm^{-2}$.