Calculate the molar mass of naturally occurring argon from the data given in the following table:
Isotope Molar Mass $(g \ mol^{-1})$ Abundance $^{36}Ar$ $35.96755$ $0.337 \%$ $^{38}Ar$ $37.96272$ $0.063 \%$ $^{40}Ar$ $39.9624$ $99.600 \%$
| Isotope | Molar Mass $(g \ mol^{-1})$ | Abundance |
| $^{36}Ar$ | $35.96755$ | $0.337 \%$ |
| $^{38}Ar$ | $37.96272$ | $0.063 \%$ |
| $^{40}Ar$ | $39.9624$ | $99.600 \%$ |
The average molar mass is calculated using the formula: $\overline{A} = \sum (f_i \times A_i)$
$\overline{A} = (0.00337 \times 35.96755) + (0.00063 \times 37.96272) + (0.99600 \times 39.9624)$
$\overline{A} = 0.12121 + 0.02392 + 39.80255$
$\overline{A} = 39.94768 \approx 39.948 \ g \ mol^{-1}$
$\overline{A} = (0.00337 \times 35.96755) + (0.00063 \times 37.96272) + (0.99600 \times 39.9624)$
$\overline{A} = 0.12121 + 0.02392 + 39.80255$
$\overline{A} = 39.94768 \approx 39.948 \ g \ mol^{-1}$
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