Why does physical adsorption decrease with an increase in temperature?

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(N/A) Physical adsorption is exothermic in nature. According to Le Chatelier's principle,an increase in temperature shifts the equilibrium in the backward direction,causing the amount of gas adsorbed to decrease. Therefore,physical adsorption occurs more readily at lower temperatures.

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Similar Questions

Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R.$
Assertion $A:$ $SO_{2(g)}$ is adsorbed to a larger extent than $H_{2(g)}$ on activated charcoal.
Reason $R:$ $SO_{2(g)}$ has a higher critical temperature than $H_{2(g)}.$
In the light of the above statements,choose the most appropriate answer from the options given below.

Assertion : Physical adsorption of molecules takes place on the surface only.
Reason : In this process,the bonds of the adsorbed molecules are broken.

$CH_4$ is adsorbed on $1 \ g$ charcoal at $0^{\circ} C$ following the Freundlich adsorption isotherm. $10.0 \ mL$ of $CH_4$ is adsorbed at $100 \ mm$ of $Hg$,whereas $15.0 \ mL$ is adsorbed at $200 \ mm$ of $Hg$. The volume of $CH_4$ adsorbed at $300 \ mm$ of $Hg$ is $10^x \ mL$. The value of $x$ is $....\times 10^{-2}$ (Nearest integer). [Use $\log_{10} 2=0.3010, \log_{10} 3=0.4771$]

Which of the following statements is true for physical adsorption?

In Langmuir's model of adsorption of a gas on a solid surface:

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