Why is [CoF_6]^{3-} considered an outer orbit | vedclass

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Question

(A) In the complex $[CoF_6]^{3-}$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$. $F^-$ is a weak field

Vedclass · Accepted Answer

It involves $sp^3d^2$ hybridization.

Vedclass · Answer

(A) In the complex $[CoF_6]^{3-}$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$. $F^-$ is a weak field ligand,which does not cause pairing of electrons in the $3d$ orbitals. Therefore,the complex utilizes the outer $4d$ orbitals for hybridization,resulting in $sp^3d^2$ hybridization. Since the outer $d$-orbitals are involved,it is classified as an outer orbital complex.

Why is $[CoF_6]^{3-}$ considered an outer orbital complex?

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