Explain the mechanism of the following reaction: $CH_3Cl + OH^-_{(aq)} \to HO-CH_3 + Cl^-$
(N/A) The reaction follows an $S_N2$ mechanism.
$1$. Kinetics: The rate of this reaction depends on the concentration of both the substrate $(CH_3Cl)$ and the nucleophile $(OH^-)$. Thus,it is a second-order (bimolecular) reaction: $\text{Rate} = k[CH_3Cl][OH^-]$.
$2$. Mechanism: It is a single-step concerted process. The nucleophile $(OH^-)$ attacks the electrophilic carbon from the side opposite to the leaving group $(Cl^-)$.
$3$. Transition State: As the $C-OH$ bond begins to form,the $C-Cl$ bond begins to break. This leads to a pentacoordinate transition state where the carbon is partially bonded to both the nucleophile and the leaving group.
$4$. Stereochemistry: The process results in the inversion of configuration (Walden inversion) at the carbon atom.
$1$. Kinetics: The rate of this reaction depends on the concentration of both the substrate $(CH_3Cl)$ and the nucleophile $(OH^-)$. Thus,it is a second-order (bimolecular) reaction: $\text{Rate} = k[CH_3Cl][OH^-]$.
$2$. Mechanism: It is a single-step concerted process. The nucleophile $(OH^-)$ attacks the electrophilic carbon from the side opposite to the leaving group $(Cl^-)$.
$3$. Transition State: As the $C-OH$ bond begins to form,the $C-Cl$ bond begins to break. This leads to a pentacoordinate transition state where the carbon is partially bonded to both the nucleophile and the leaving group.
$4$. Stereochemistry: The process results in the inversion of configuration (Walden inversion) at the carbon atom.
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Similar Questions
Given below are two statements:
Statement $I$: $(CH_3)_3C-CH_2-Cl$ will undergo $S_N1$ reaction even though it is a primary halide.
Statement $II$: It will not undergo $S_N2$ reaction very easily even though it is a primary halide.
In the light of the above statements, choose the most appropriate answer from the options given below:
Statement $I$: $(CH_3)_3C-CH_2-Cl$ will undergo $S_N1$ reaction even though it is a primary halide.
Statement $II$: It will not undergo $S_N2$ reaction very easily even though it is a primary halide.
In the light of the above statements, choose the most appropriate answer from the options given below:
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